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5x^2+235x-720=0
a = 5; b = 235; c = -720;
Δ = b2-4ac
Δ = 2352-4·5·(-720)
Δ = 69625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{69625}=\sqrt{25*2785}=\sqrt{25}*\sqrt{2785}=5\sqrt{2785}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(235)-5\sqrt{2785}}{2*5}=\frac{-235-5\sqrt{2785}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(235)+5\sqrt{2785}}{2*5}=\frac{-235+5\sqrt{2785}}{10} $
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